27c^2-12c+18c-8=0

Solution for 27c^2-12c+18c-8=0 equation:

27c^2-12c+18c-8=0

We add all the numbers together, and all the variables

27c^2+6c-8=0

a = 27; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·27·(-8)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*27}=\frac{-36}{54}
=-2/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*27}=\frac{24}{54}
=4/9
$